Which of the following aqueous solutions has | vedclass

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(A) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$. Since $K_b$ is constant for the solvent,the solution with the hig

Vedclass · Accepted Answer

$0.01 \, M \, Na_2SO_4$

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(A) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$. Since $K_b$ is constant for the solvent,the solution with the highest value of $i 	imes m$ will have the highest boiling point.For $0.01 \, M \, Na_2SO_4$,$i = 3$ $(2Na^+ + SO_4^{2-})$,so $i 	imes m = 3 	imes 0.01 = 0.03$.For $0.01 \, M \, KNO_3$,$i = 2$ $(K^+ + NO_3^-)$,so $i 	imes m = 2 	imes 0.01 = 0.02$.For $0.015 \, M \, 	ext{Urea}$,$i = 1$ (non-electrolyte),so $i 	imes m = 1 	imes 0.015 = 0.015$.For $0.015 \, M \, 	ext{Glucose}$,$i = 1$ (non-electrolyte),so $i 	imes m = 1 	imes 0.015 = 0.015$.Comparing the values,$0.03 > 0.02 > 0.015$. Thus,$0.01 \, M \, Na_2SO_4$ has the highest boiling point.

Which of the following aqueous solutions has the highest boiling point?

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