Calculate the osmotic pressure of a 20% (w/v) | vedclass

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Question

(C) $CaCl_2 	o Ca^{2+} + 2Cl^-$Before dissociation$1$$0$$0$After dissociation$1-\alpha$$\alpha$$2\alpha$Given: $w = 20 	ext{ g}$, $V = 100 	ext{ mL

Vedclass · Accepted Answer

$121.14$

Vedclass · Answer

(C) $CaCl_2 	o Ca^{2+} + 2Cl^-$Before dissociation$1$$0$$0$After dissociation$1-\alpha$$\alpha$$2\alpha$Given: $w = 20 	ext{ g}$, $V = 100 	ext{ mL} = 0.1 	ext{ L}$, $T = 273 	ext{ K}$, $R = 0.0821 	ext{ L atm K}^{-1} 	ext{ mol}^{-1}$.Molar mass of $CaCl_2$ $(M)$ $= 40 + 2 	imes 35.5 = 111 	ext{ g/mol}$.Van't Hoff factor $(i)$ for $100\%$ ionization $(\alpha = 1)$: $i = 1 + (n-1)\alpha = 1 + (3-1)(1) = 3$.Osmotic pressure $(\pi)$ formula: $\pi = i 	imes C 	imes R 	imes T = i 	imes (w / (M 	imes V)) 	imes R 	imes T$.$\pi = 3 	imes (20 / (111 	imes 0.1)) 	imes 0.0821 	imes 273$.$\pi = 3 	imes 1.8018 	imes 22.4133 = 121.14 	ext{ atm}$.

Calculate the osmotic pressure of a $20\%$ (w/v) anhydrous $CaCl_2$ solution at $0^\circ C$. Assume $100\%$ ionization. (in $\text{atm}$)

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