Class 11PhysicsSystem of Particles and Rotational MotionCentre of Mass of Composite Bodies and Cavity Problen of Centre of mass
Medium$A$ uniform square plate is shown in the figure. Four identical small squares are removed from its corners. Where will the $C.M.$ (Center of Mass) be located after removing all four squares? Give the answer in terms of quadrants and axes.
- AAt point $O$
- BIn the $III$ quadrant
- COn the $OY'$ axis
- DIn the $IV$ quadrant
Explore More
Similar Questions
From a uniform square plate,one-fourth part is removed as shown. The centre of mass of the remaining part will lie on:
Easy
View SolutionConsider a circular disc of radius $20 \ cm$ with centre located at the origin. $A$ circular hole of radius $5 \ cm$ is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of the centre of mass of the residual or remaining disc from the origin will be (in $cm$)
$A$ circular disc of radius $R$ has a uniform thickness. $A$ circular hole of diameter equal to the radius of the disc has been cut out as shown. The distance of the centre of mass of the remaining disc from point $O$ is
Difficult
View SolutionThe sector of a circular plate shown in the figure has its center of mass at $y_{CM} =$
Difficult
View SolutionFrom a circular disc of radius $R$,a square is cut out with a radius as its diagonal. The center of mass of the remaining part is at a distance (from the centre) of:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo