As shown in the figure,a small wheel is coaxi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Since both wheels are connected coaxially,they rotate with the same angular velocity $\omega$.Let $R$ be the radius of the small wheel and $2R$ be

Vedclass · Accepted Answer

$y = 2x$

Vedclass · Answer

(C) Since both wheels are connected coaxially,they rotate with the same angular velocity $\omega$.Let $R$ be the radius of the small wheel and $2R$ be the radius of the large wheel.The distance covered by a string attached to a wheel is given by $s = r	heta$,where $r$ is the radius and $	heta$ is the angle of rotation.For the same time interval,both wheels rotate by the same angle $	heta$.For string $A$ on the small wheel: $x = R	heta$.For string $B$ on the large wheel: $y = (2R)	heta$.Dividing the two equations: $y/x = (2R	heta) / (R	heta) = 2$.Therefore,$y = 2x$.

Similar Questions

$A$ rod of length $1 \ m$ is held vertically. What will be the speed of the other end when it touches the ground without slipping?

In the rotational motion of a rigid body,all particles of the body have

As shown in the figure,a mass $m = 500 \ g$ hangs from the rim of a wheel of radius $r = 20 \ cm$. When released from rest,the mass falls $2.0 \ m$ in $8 \ s$. Then the moment of inertia of the wheel is .......... $kg \cdot m^2$. $(g = 10 \ m/s^2)$

What is the direction of angular velocity in circular motion about a fixed axis of rotation?

$A$ mass $m$ is supported by a massless string wound around a uniform hollow cylinder of mass $m$ and radius $R$. If the string does not slip on the cylinder,with what acceleration will the mass fall on release?

Vedclass Test Series

Exam Paper Generator

Online Exam Module