(C) The moment of inertia of a solid cylinder about its axis is given by:$I = \frac{1}{2} M R^2$Substituting the given values ($M = 20 \ kg$,$R = 0.25

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(C) The moment of inertia of a solid cylinder about its axis is given by:$I = \frac{1}{2} M R^2$Substituting the given values ($M = 20 \ kg$,$R = 0.25 \ m$):$I = \frac{1}{2} \times 20 \times (0.25)^2 = 10 \times 0.0625 = 0.625 \ kg \cdot m^2$The angular momentum $L$ is given by the product of the moment of inertia and angular velocity $(\omega)$:$L = I \omega$Given $\omega = 100 \ rad \cdot s^{-1}$:$L = 0.625 \times 100 = 62.5 \ J \cdot s$

Class 11 Physics System of Particles and Rotational Motion Angular Momentum and Angular Impulse

Medium

$A$ solid cylinder of mass $20 \ kg$ rotates about its axis with an angular speed of $100 \ rad \cdot s^{-1}$. The radius of the cylinder is $0.25 \ m$. The magnitude of its angular momentum about the axis of the cylinder is ........ $J \cdot s$.

A
$55.5$
B
$6.25$
C
$62.5$
D
$20.6$

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System of Particles and Rotational Motion

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Angular Momentum and Angular Impulse

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$A$ solid cylinder of mass $20 \ kg$ rotates about its axis with an angular speed of $100 \ rad \cdot s^{-1}$. The radius of the cylinder is $0.25 \ m$. The magnitude of its angular momentum about the axis of the cylinder is ........ $J \cdot s$.

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