The angular momentum of a body rotating about a fixed axis is increased by $10\%$. What is the percentage increase in its rotational kinetic energy (in $\%$)?

Two bodies $A$ and $B$ are rotating freely with moments of inertia $I_A$ and $I_B$ respectively. Given $I_A > I_B$ and their angular momenta are equal. If $K_A$ and $K_B$ are their rotational kinetic energies,then:

If the angular velocity of a body rotating about a given axis increases by $20 \%$,then its kinetic energy of rotation will increase by: (in $\%$)

$A$ flywheel is in the form of a solid circular disc with a mass of $72 \ kg$ and a radius of $0.5 \ m$. If it rotates at $70 \ rpm$,its rotational kinetic energy is ........ $J$.

$A$ solid spherical ball of mass $1 \, kg$ and radius $3 \, cm$ is rotating with an angular velocity of $50 \, rad/s$ about an axis passing through its center. The rotational kinetic energy is:

$A$ thin rod of length $L$ is suspended from one end and rotates with $n$ revolutions per second. What will be the rotational kinetic energy of the rod?