The coordinates of the center of mass of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a uniform triangular lamina,the center of mass is located at the centroid of the triangle.If the vertices of the right-angled triangle are at

Vedclass · Accepted Answer

$\left( \frac{b}{3}, \frac{h}{3} \right)$

Vedclass · Answer

(C) For a uniform triangular lamina,the center of mass is located at the centroid of the triangle.If the vertices of the right-angled triangle are at $(0, 0)$,$(b, 0)$,and $(0, h)$,the coordinates of the center of mass $(x_{cm}, y_{cm})$ are given by the average of the coordinates of the vertices:$x_{cm} = \frac{x_1 + x_2 + x_3}{3} = \frac{0 + b + 0}{3} = \frac{b}{3}$$y_{cm} = \frac{y_1 + y_2 + y_3}{3} = \frac{0 + 0 + h}{3} = \frac{h}{3}$Therefore,the coordinates of the center of mass are $\left( \frac{b}{3}, \frac{h}{3} \right)$.

The coordinates of the center of mass of the triangular lamina shown in the figure are ....... .

Similar Questions

Write the meaning of homogeneous bodies.

Mass is distributed uniformly over a thin rectangular plate,and the positions of two vertices are given by $(1, 3)$ and $(2, -4)$. What is the position of the $3^{rd}$ vertex if the centre of mass of the plate lies at the origin?

To find the centre of mass of a rigid body,why is it not possible to know $\sum m_i \vec{r}_i$ for all the particles?

The centre of mass of a system of two particles of masses $m_1$ and $m_2$ separated by a distance $d$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module