What is the kinetic energy of one gram mole of a gas at standard temperature and pressure? $(R = 8.31 \ J/mol \cdot K)$

Molecular motion shows itself as

On colliding in a closed container,the gas molecules:

In an ideal gas at temperature $T$,the average force that a molecule applies on the walls of a closed container depends on $T$ as $T^{x}$. The value of $x$ is

$Assertion$: The total translational kinetic energy of all the molecules of a given mass of an ideal gas is $1.5$ times the product of its pressure and its volume.
$Reason$: The molecules of a gas collide with each other and the velocities of the molecules change due to the collision.

If the average kinetic energy of a gas molecule at $27^{\circ} C$ is $3.3 \times 10^{-20} \,J$, then the average kinetic energy of the gas molecules at $127^{\circ} C$ is