The v_{rms} of gas molecules in a container i | vedclass

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(C) The root mean square velocity $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas

Vedclass · Accepted Answer

$400$

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(C) The root mean square velocity $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.Since the temperature $(T)$ remains constant and the nature of the gas $(M)$ does not change,the $v_{rms}$ depends only on the temperature.Even if the amount of gas in the container decreases due to leakage,the temperature remains constant.Therefore,the $v_{rms}$ of the remaining gas molecules remains unchanged at $400 \ ms^{-1}$.

The $v_{rms}$ of gas molecules in a container is $400 \ ms^{-1}$. If half of the gas leaks out of the container at a constant temperature,the $v_{rms}$ of the remaining gas molecules will be . . . . . . $ms^{-1}$.

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