The floor area of a room is 20 , m^2 and its | vedclass

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(A) Given: Pressure $P = 1 \, atm = 1.01 	imes 10^5 \, N \, m^{-2}$.Volume $V = 	ext{Area} 	imes 	ext{Height} = 20 \, m^2 	imes 3 \, m = 60 \, m^

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$70.5 \, kg$

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(A) Given: Pressure $P = 1 \, atm = 1.01 	imes 10^5 \, N \, m^{-2}$.Volume $V = 	ext{Area} 	imes 	ext{Height} = 20 \, m^2 	imes 3 \, m = 60 \, m^3$.Temperature $T = 27 \, ^\circ C = 27 + 273 = 300 \, K$.Universal gas constant $R = 8.31 \, J \, mol^{-1} K^{-1}$.Molar mass of air $M = 29 \, g/mol = 0.029 \, kg/mol$.Using the ideal gas equation $PV = nRT$,where $n$ is the number of moles:$n = \frac{PV}{RT} = \frac{1.01 	imes 10^5 	imes 60}{8.31 	imes 300} \approx 2430.8 \, mol$.The mass of the air $m = n 	imes M = 2430.8 	imes 0.029 \approx 70.49 \, kg \approx 70.5 \, kg$.

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