The $rms$ speed of oxygen at $27^{\circ}C$ will be .... $ms^{-1}$.

The root mean square velocity of a gas molecule of mass $m$ at a given temperature is proportional to

The $rms$ speed of an ideal diatomic gas at temperature $T$ is $v$. When the gas dissociates into atoms,its new $rms$ speed becomes double. At what temperature does the dissociation of the gas occur?

The temperature of an ideal gas is increased from $120 \ K$ to $480 \ K.$ If at $120 \ K,$ the root mean square velocity of the gas molecules is $v,$ at $480 \ K$ it becomes

Temperature of an ideal gas, initially at $27^{\circ} C$, is raised by $6^{\circ} C$. The rms velocity of the gas molecules will

At a given temperature,the $rms$ velocity of a gas molecule of mass $m$ is proportional to: