Which stable nucleus has a radius that is hal | vedclass

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(D) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number.Given that the radius of the unknown nucleus is hal

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$Li^7$

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(D) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number.Given that the radius of the unknown nucleus is half the radius of $Fe^{56}$,we have:$R_{new} = \frac{1}{2} R_{Fe}$$R_0 (A_{new})^{1/3} = \frac{1}{2} R_0 (A_{Fe})^{1/3}$$(A_{new})^{1/3} = \frac{1}{2} (56)^{1/3}$Taking the cube of both sides:$A_{new} = (\frac{1}{2})^3 	imes 56$$A_{new} = \frac{1}{8} 	imes 56 = 7$Therefore,the nucleus with mass number $A = 7$ is $Li^7$.

Which stable nucleus has a radius that is half that of $Fe^{56}$?

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