In a nuclear fusion process,if the masses of | vedclass

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(B) In a nuclear fusion process,two lighter nuclei combine to form a heavier nucleus. Due to the mass defect,the mass of the product nucleus $(m_3)$ i

Vedclass · Accepted Answer

$m_3 < ( m_1 + m_2 )$

Vedclass · Answer

(B) In a nuclear fusion process,two lighter nuclei combine to form a heavier nucleus. Due to the mass defect,the mass of the product nucleus $(m_3)$ is always less than the sum of the masses of the reactant nuclei $(m_1 + m_2)$. The lost mass is converted into energy according to Einstein's mass-energy equivalence relation,$E = \Delta m c^2$. Therefore,$m_3 < m_1 + m_2$.

In a nuclear fusion process,if the masses of the reactant nuclei are $m_1$ and $m_2$,and the mass of the resulting nucleus is $m_3$,then which of the following is true?

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