The binding energy per nucleon for a deuteron | vedclass

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(C) The nuclear fusion reaction is given by: $2(_1^2H) 	o _2^4He + Q$.The binding energy of a deuteron nucleus is $BE_d = 2 	imes 1.1 \, MeV = 2.2 \

Vedclass · Accepted Answer

$23.6$

Vedclass · Answer

(C) The nuclear fusion reaction is given by: $2(_1^2H) 	o _2^4He + Q$.The binding energy of a deuteron nucleus is $BE_d = 2 	imes 1.1 \, MeV = 2.2 \, MeV$.The binding energy of a helium nucleus is $BE_{He} = 4 	imes 7 \, MeV = 28 \, MeV$.The energy released $Q$ is the difference between the total binding energy of the products and the total binding energy of the reactants:$Q = BE_{He} - 2 	imes BE_d$$Q = 28 \, MeV - 2 	imes (2.2 \, MeV)$$Q = 28 \, MeV - 4.4 \, MeV = 23.6 \, MeV$.

The binding energy per nucleon for a deuteron and helium are $1.1 \, MeV$ and $7 \, MeV$ respectively. If two deuteron nuclei fuse to form one helium nucleus,the energy released is $...... \, MeV$.

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