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Question

(A) The energy of the second excited state is given as $E = 108.8 \ eV$.To convert this energy into Joules,we multiply by the elementary charge $e = 1

Vedclass · Accepted Answer

$5.8 	imes 10^{-26}$

Vedclass · Answer

(A) The energy of the second excited state is given as $E = 108.8 \ eV$.To convert this energy into Joules,we multiply by the elementary charge $e = 1.6 	imes 10^{-19} \ C$:$E = 108.8 	imes 1.6 	imes 10^{-19} \ J$.The momentum $p$ of a photon (or the recoil momentum of the atom emitting it) is given by the relation $p = \frac{E}{c}$,where $c = 3 	imes 10^8 \ m/s$ is the speed of light.Substituting the values:$p = \frac{108.8 	imes 1.6 	imes 10^{-19}}{3 	imes 10^8}$$p = \frac{174.08 	imes 10^{-19}}{3 	imes 10^8}$$p \approx 58.026 	imes 10^{-27} \ kg \ m/s$$p \approx 5.8 	imes 10^{-26} \ kg \ m/s$.

When the potential energy of the second excited state of an atom is $108.8 \ eV$,the recoil momentum of the atom is ...... $kg \ m/s$.

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