The half-life of the radioisotope tritium (_1 | vedclass

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(B) The half-life of tritium is $T_{1/2} = 12.3 \ 	ext{years}$.The amount remaining after time $t$ is given by the formula $N = \frac{N_0}{2^n}$, whe

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(B) The half-life of tritium is $T_{1/2} = 12.3 \ 	ext{years}$.The amount remaining after time $t$ is given by the formula $N = \frac{N_0}{2^n}$, where $n = \frac{t}{T_{1/2}}$ is the number of half-lives.Given $t = 49.2 \ 	ext{years}$ and $T_{1/2} = 12.3 \ 	ext{years}$, the number of half-lives is $n = \frac{49.2}{12.3} = 4$.Substituting the values into the formula: $N = \frac{32}{2^4} = \frac{32}{16} = 2 \ mg$.Therefore, $2 \ mg$ of tritium will remain after $49.2$ years.

The half-life of the radioisotope tritium $(_1^3H)$ is $12.3$ years. If the initial amount of tritium is $32 \ mg$, how much amount (in $mg$) will remain after $49.2$ years?

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