$A$ $\gamma$-ray photon creates an electron-positron pair. If the rest mass energy of an electron is $0.51 \, MeV$ and the total kinetic energy of the electron-positron pair is $0.78 \, MeV$,then the energy of the $\gamma$-ray photon in $MeV$ is:
- A$0.78$
- B$1.8$
- C$1.28$
- D$0.28$
Explore More
Similar Questions
$A$ nucleus with mass number $220$ initially at rest emits an alpha particle. If the $Q$ value of the reaction is $5.5 \ MeV$,calculate the kinetic energy of the alpha particle. (in $MeV$)
DifficultKCET 2023
View SolutionCalculate and compare the energy released by
$(a)$ fusion of $1.0 \; kg$ of hydrogen deep within the Sun and
$(b)$ the fission of $1.0 \; kg$ of $^{235} U$ in a fission reactor.
$(a)$ fusion of $1.0 \; kg$ of hydrogen deep within the Sun and
$(b)$ the fission of $1.0 \; kg$ of $^{235} U$ in a fission reactor.
Medium
View SolutionWhich of the following is used as a moderator in nuclear reactors?
The energy liberated per nuclear fission is $200 \; MeV$. If $10^{20}$ fissions occur per second,the amount of power produced will be:
MediumNEET 2017
View Solution$113$. Energy released in the fission of a single uranium nucleus is $200 \text{ MeV}$. Then the number of fissions per second to produce $5 \text{ mW}$ power is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo