In the nuclear fusion reaction _1^2H + _1^3H | vedclass

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(D) The reaction is $_1^2H + _1^3H 	o _2^4He + n$.To initiate the fusion reaction,the average thermal kinetic energy of the nuclei must be equal to t

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$10^9 \, K$

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(D) The reaction is $_1^2H + _1^3H 	o _2^4He + n$.To initiate the fusion reaction,the average thermal kinetic energy of the nuclei must be equal to the repulsive potential energy barrier.The average thermal kinetic energy is given by $E = \frac{3}{2}kT$.Equating the thermal energy to the repulsive potential energy:$\frac{3}{2}kT = 7.7 	imes 10^{-14} \, J$.Substituting the value of $k = 1.38 	imes 10^{-23} \, J/K$:$T = \frac{2 	imes 7.7 	imes 10^{-14}}{3 	imes 1.38 	imes 10^{-23}}$.$T = \frac{15.4}{4.14} 	imes 10^9 \, K$.$T \approx 3.7 	imes 10^9 \, K$.Rounding to the nearest order of magnitude,$T \approx 10^9 \, K$.

In the nuclear fusion reaction $_1^2H + _1^3H \to _2^4He + n$,the repulsive potential energy between the two nuclei is $7.7 \times 10^{-14} \, J$. To what temperature must the gas be heated to initiate the reaction? $[k = 1.38 \times 10^{-23} \, J/K]$

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