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(D) In this region,the charged particle experiences an electric force given by $\vec{F_e} = q\vec{E}$.Since the particle starts from rest,it will begi

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(D) In this region,the charged particle experiences an electric force given by $\vec{F_e} = q\vec{E}$.Since the particle starts from rest,it will begin to accelerate in the direction of the electric field (if positive) or opposite to it (if negative).As the particle gains velocity $\vec{v}$,it experiences a magnetic force given by $\vec{F_m} = q(\vec{v} 	imes \vec{B})$.Since the electric and magnetic fields are parallel,and the particle's velocity $\vec{v}$ is generated by the electric field,the velocity $\vec{v}$ will always be parallel to the magnetic field $\vec{B}$ (i.e.,$\vec{v} \parallel \vec{B}$).Therefore,the magnetic force $F_m = qvB \sin(0^\circ) = 0$.Since there is no magnetic force acting on the particle and the electric force acts along the line of the fields,the particle will move in a straight line.

In a region,there are uniform and constant electric and magnetic fields. Both these fields are parallel to each other. $A$ stationary charged particle is released in this region. The path of the particle will be.......

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