The magnitude of the charge of an electric di | vedclass

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Question

(C) The dipole moment $p$ is defined as the product of the magnitude of one of the charges $q$ and the distance between them $2a$.Given:Charge $q = 3.

Vedclass · Accepted Answer

$7.68 	imes 10^{-29}$

Vedclass · Answer

(C) The dipole moment $p$ is defined as the product of the magnitude of one of the charges $q$ and the distance between them $2a$.Given:Charge $q = 3.2 	imes 10^{-19} \ C$Distance $2a = 2.4 \ \mathring{A} = 2.4 	imes 10^{-10} \ m$Electric field $E = 4 	imes 10^5 \ V/m$ (Note: The electric field is extra information not required to calculate the dipole moment).Formula: $p = q 	imes (2a)$Calculation: $p = (3.2 	imes 10^{-19} \ C) 	imes (2.4 	imes 10^{-10} \ m)$$p = 7.68 	imes 10^{-29} \ C-m$.

The magnitude of the charge of an electric dipole is $3.2 \times 10^{-19} \ C$ and the distance between them is $2.4 \ \mathring{A}$. If it is placed in an electric field of $4 \times 10^5 \ V/m$,then its dipole moment (in $C-m$) is .......

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