Class 12PhysicsElectric Potential and CapacitanceRelation between Electric Field and Potential and Potential Gradient
EasyTwo parallel plates are separated by a distance of $5 \, mm$. The potential difference between them is $50 \, V$. $A$ particle of mass $10^{-15} \, kg$ and charge $10^{-11} \, C$ enters the region with a velocity of $10^7 \, m/s$. The acceleration of the particle will be:
- A$10^8 \, m/s^2$
- B$5 \times 10^5 \, m/s^2$
- C$10^5 \, m/s^2$
- D$2 \times 10^3 \, m/s^2$
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DifficultAP EAMCET 2022
View SolutionElectric field at a point $(x, y, z)$ is represented by $\vec E = 2x\hat i + y^2\hat j$. If the potential at $(0, 0, 0)$ is $2 \, V$,find the potential at $(1, 1, 1)$. (in $/3$)
Medium
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