When a series combination of $2.0\ \mu F$ and $8.0\ \mu F$ capacitors is connected to a $300\ V$ potential difference,the charge on the $2.0\ \mu F$ capacitor is .....

  • A
    $2.4 \times 10^{-4}\ C$
  • B
    $4.8 \times 10^{-4}\ C$
  • C
    $7.2 \times 10^{-4}\ C$
  • D
    $9.6 \times 10^{-4}\ C$

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Three capacitors $2 \mu F$,$3 \mu F$,and $5 \mu F$ can withstand voltages up to $3 \, V$,$2 \, V$,and $1 \, V$ respectively. Their series combination can withstand a maximum voltage equal to.....$V$.

Ten capacitors are joined in parallel and charged with a battery up to a potential $V$. They are then disconnected from the battery and joined again in series. The potential of this combination will be ....... $V$.

From the circuit given below, the capacitance between terminals $A$ and $B$ is . . . . . . $\mu\text{F}$. (Take $C_1 = C_2 = C_3 = 1\text{ }\mu\text{F}$ and $C_4 = 2\text{ }\mu\text{F}$.)

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In the given circuit,what is the potential difference across the $4.5\ \mu F$ capacitor in $V$?

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