An electric dipole with dipole moment p is pl | vedclass

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(D) The work done $W$ in rotating an electric dipole in an electric field from an initial angle $	heta_1$ to a final angle $	heta_2$ is given by the

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$2pE$

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(D) The work done $W$ in rotating an electric dipole in an electric field from an initial angle $	heta_1$ to a final angle $	heta_2$ is given by the formula: $W = pE(\cos	heta_1 - \cos	heta_2)$.Given that the dipole is initially parallel to the field,the initial angle $	heta_1 = 0^{\circ}$.The final angle is $	heta_2 = 180^{\circ}$.Substituting these values into the formula:$W = pE(\cos 0^{\circ} - \cos 180^{\circ})$$W = pE(1 - (-1))$$W = pE(1 + 1)$$W = 2pE$.Therefore,the work done by the external agent is $2pE$.

An electric dipole with dipole moment $p$ is placed in an electric field of intensity $E$. Initially,the dipole is parallel to the field. What is the work done by an external agent to rotate the dipole by $180^{\circ}$ in the electric field?

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