Two capacitors $C_1$ and $C_2$ are charged to $120 \ V$ and $200 \ V$ respectively. It is found that by connecting them together,the potential on each can be made zero. Then:

  • A
    $5C_1 = 3C_2$
  • B
    $3C_1 = 5C_2$
  • C
    $3C_1 + 5C_2 = 0$
  • D
    $9C_1 = 4C_2$

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