What is the area of the plates of a capacitor | vedclass

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(A) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$.Rearranging the formula to solve for the are

Vedclass · Accepted Answer

$1.694 	imes 10^9 \ m^2$

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(A) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$.Rearranging the formula to solve for the area $A$,we get $A = \frac{Cd}{\varepsilon_0}$.Given values are $C = 3 \ F$,$d = 5 \ mm = 5 	imes 10^{-3} \ m$,and $\varepsilon_0 = 8.85 	imes 10^{-12} \ F/m$.Substituting these values into the equation:$A = \frac{3 	imes 5 	imes 10^{-3}}{8.85 	imes 10^{-12}}$$A = \frac{15 	imes 10^{-3}}{8.85 	imes 10^{-12}}$$A \approx 1.694 	imes 10^9 \ m^2$.

What is the area of the plates of a capacitor with a capacitance of $3 \ F$? The distance between the two plates is $5 \ mm$.

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