A particle of mass 2 times 10^{-5} kg and ch | vedclass

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Question

(B) Given: Mass $m = 2 	imes 10^{-5} \ kg$,charge $q = 4 	imes 10^{-3} \ C$,electric field $E = 5 \ V/m$,initial velocity $u = 0$,time $t = 10 \ s$.

Vedclass · Accepted Answer

$10^3 \ J$

Vedclass · Answer

(B) Given: Mass $m = 2 	imes 10^{-5} \ kg$,charge $q = 4 	imes 10^{-3} \ C$,electric field $E = 5 \ V/m$,initial velocity $u = 0$,time $t = 10 \ s$.The force acting on the particle is $F = qE$.The acceleration of the particle is $a = \frac{F}{m} = \frac{qE}{m}$.Substituting the values: $a = \frac{4 	imes 10^{-3} 	imes 5}{2 	imes 10^{-5}} = \frac{20 	imes 10^{-3}}{2 	imes 10^{-5}} = 10 	imes 10^2 = 10^3 \ m/s^2$.Using the equation of motion $v = u + at$,where $u = 0$:$v = 0 + (10^3 \ m/s^2)(10 \ s) = 10^4 \ m/s$.The kinetic energy $K$ after $10 \ s$ is given by $K = \frac{1}{2}mv^2$.$K = \frac{1}{2} 	imes (2 	imes 10^{-5} \ kg) 	imes (10^4 \ m/s)^2$.$K = 10^{-5} 	imes 10^8 = 10^3 \ J$.

$A$ particle of mass $2 \times 10^{-5} \ kg$ and charge $4 \times 10^{-3} \ C$ starts from rest in a uniform electric field of $5 \ V/m$. What is its kinetic energy after $10 \ s$?

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