To obtain a NOR gate,what is the minimum numb | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $NOR$ gate can be constructed using $NAND$ gates by following these steps:$1$. Connect the inputs of two $NAND$ gates together to act as $NOT$ gat

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) $NOR$ gate can be constructed using $NAND$ gates by following these steps:$1$. Connect the inputs of two $NAND$ gates together to act as $NOT$ gates (inverters).$2$. Feed the inputs $A$ and $B$ into these two $NOT$ gates to get $\bar{A}$ and $\bar{B}$.$3$. Connect $\bar{A}$ and $\bar{B}$ to the inputs of a third $NAND$ gate.$4$. The output of this third $NAND$ gate will be $\overline{\bar{A} \cdot \bar{B}}$.$5$. By De Morgan's Law,$\overline{\bar{A} \cdot \bar{B}} = A + B$,which is the output of an $OR$ gate.$6$. To get a $NOR$ gate,we need to invert this output,requiring a fourth $NAND$ gate used as a $NOT$ gate.$7$. However,a more efficient configuration exists using $4$ $NAND$ gates to realize a $NOR$ gate. Thus,the minimum number of $NAND$ gates required is $4$.

To obtain a $NOR$ gate,what is the minimum number of $NAND$ gates required?

Similar Questions

The output of the given combination of logic gates represents:

You are given two circuits as shown in the figure,which consist of $NAND$ gates. Identify the logic operation carried out by the two circuits.

Which logic gate is represented by the following combination of logic gates?

In Boolean algebra,$Y = A + B$ represents . . . . . .

In the following logic circuit, the values of $Y_1, Y_2$ and $Y_3$ are respectively

Vedclass Test Series

Exam Paper Generator

Online Exam Module