For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

The phase difference between the input voltage and the output voltage in a common emitter amplifier is (in $^{\circ}$)

For a transistor,in a common emitter arrangement,the alternating current gain $\beta$ is given by

In an $N-P-N$ transistor circuit,the common emitter configuration is used. $A$ load resistor $R_L$ is connected to the collector and a base resistor $R_B$ is connected to the base. Given $V_{CC} = 8V$,$V_{CE} = 4V$,$V_{BE} = 0.6V$,collector current $I_C = 4mA$,and current gain $\beta = 100$,find the values of $R_L$ and $R_B$ respectively.

If $ \alpha $-current gain of a transistor is $ 0.98 $,what is the value of $ \beta $-current gain of the transistor?

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then: