$A$ common emitter amplifier has a voltage gain of $50$, an input resistance of $100 \ \Omega$, and an output resistance of $200 \ \Omega$. What is the power gain of the amplifier?

In an $NPN$ transistor,the collector current is $10\, mA$. If $90\%$ of the electrons emitted reach the collector,then:

$A$ transistor is used in an amplifier circuit in common emitter mode. If the base current changes by $100 \,\mu A$, it brings a change of $10 \,mA$ in collector current. If the load resistance is $2 \,k \Omega$ and input resistance is $1 \,k \Omega$, the value of power gain is $x \times 10^{4}$. The value of $x$ is . . . . . . .

An $n-p-n$ transistor can be considered to be equivalent to two diodes connected back-to-back. Which of the following figures correctly represents this equivalent circuit?

$A$ transistor is connected in a common base circuit with $\beta = 75$. For an emitter current of $5 \text{ mA}$,the value of the collector current is ........ $\text{mA}$.

In a common emitter configuration with suitable bias,it is given that $R_L$ is the load resistance and $R_{BE}$ is the small signal dynamic resistance (input side). Then,the voltage gain,current gain,and power gain are given,respectively,by: [$\beta$ is the current gain,$I_B$,$I_C$,$I_E$ are respectively base,collector,and emitter currents]