In an $NPN$ transistor circuit,the collector current is $10 \ mA$. If $95\%$ of the electrons emitted reach the collector,what is the base current in $mA$?

While a collector to emitter voltage is constant in a transistor, the collector current changes by $8.2 \,mA$ when the emitter current changes by $8.3 \,mA$. The value of forward current ratio is

$A$ transistor is connected in common emitter circuit configuration. The collector supply voltage is $10 \, V$ and the voltage drop across a resistor of $1000 \, \Omega$ in the collector circuit is $0.6 \, V$. If the current gain factor $(\beta)$ is $24$,then the base current is $.... \, \mu A$. (Round off to the Nearest Integer)

An $n-p-n$ transistor power amplifier in $C-E$ configuration gives

In a $CE$ transistor, a change of $8.0 \,mA$ in the emitter current produces a change of $7.8 \,mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current (in $\mu A$)?

In a common base amplifier circuit,calculate the change in base current if the change in emitter current is $2\, mA$ and $\alpha = 0.98$.