In the given common-emitter circuit, an $npn$ transistor with $\beta = 100$ is connected. What is the output voltage of the amplifier?

Three amplifiers,each having a voltage gain of $10$,are connected in series. The resultant gain would be

$A$ transistor has a current amplification factor of $60$. In a $CE$ amplifier, input resistance is $1 \, k\Omega$ and output voltage is $0.01 \, V$. The transconductance is (in $SI$ units)

$A$ transistor is connected in common emitter configuration. The collector supply is $8 V$ and the voltage drop across a resistor of $800 \Omega$ in the collector circuit is $0.5 V$. If the current gain factor $\alpha$ is $0.96$,the base current is

In an $N-P-N$ transistor circuit,the common emitter configuration is used. $A$ load resistor $R_L$ is connected to the collector and a base resistor $R_B$ is connected to the base. Given $V_{CC} = 8V$,$V_{CE} = 4V$,$V_{BE} = 0.6V$,collector current $I_C = 4mA$,and current gain $\beta = 100$,find the values of $R_L$ and $R_B$ respectively.

The value of $I_c$ for the configuration shown is in $mA$.