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(C) From the collector circuit,applying Kirchhoff's Voltage Law $(KVL)$:$V_{CC} = I_C R_C + V_{CE}$Given $V_{CC} = 10 	ext{ V}$,$V_{CE} = 5 	ext{ V}

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$200 	imes 10^3 \Omega$

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(C) From the collector circuit,applying Kirchhoff's Voltage Law $(KVL)$:$V_{CC} = I_C R_C + V_{CE}$Given $V_{CC} = 10 	ext{ V}$,$V_{CE} = 5 	ext{ V}$,and $R_C = 1 	ext{ k}\Omega = 1000 \Omega$.$10 = I_C (1000) + 5$$I_C = \frac{5}{1000} = 5 	imes 10^{-3} 	ext{ A} = 5 	ext{ mA}$.Now,for the base circuit:$V_{CC} = I_B R_b + V_{BE}$Given $V_{BE} = 0$ and $V_{CC} = 10 	ext{ V}$.Since $\beta = \frac{I_C}{I_B}$,we have $I_B = \frac{I_C}{\beta} = \frac{5 	imes 10^{-3}}{100} = 5 	imes 10^{-5} 	ext{ A}$.Substituting into the base circuit equation:$10 = (5 	imes 10^{-5}) R_b + 0$$R_b = \frac{10}{5 	imes 10^{-5}} = 2 	imes 10^5 \Omega = 200 	imes 10^3 \Omega$.

In the given circuit,a transistor with a current gain $\beta = 100$ is used. To have $V_{CE} = 5 \text{ V}$ and $V_{BE} = 0$,what should be the value of the base resistance $R_b$?

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