The I-V characteristic of an LED is: | vedclass

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(B) The wavelength of light emitted by an $LED$ is given by $\lambda = \frac{hc}{E_g}$, which implies $\lambda \propto \frac{1}{E_g}$.Option $B$ repre

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(B) The wavelength of light emitted by an $LED$ is given by $\lambda = \frac{hc}{E_g}$, which implies $\lambda \propto \frac{1}{E_g}$.Option $B$ represents the forward bias characteristics of a diode. Since the wavelength of red light is the largest, it requires the smallest bandgap energy $E_g$, while blue light requires the largest energy for emission.From the graph, it is clear that the $Cut-in$ voltage is smallest for red $(R)$ and largest for blue $(B)$, which is consistent with the relationship between energy and wavelength.

The $I-V$ characteristic of an $LED$ is:

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