Two plane mirrors A and B are placed parallel | vedclass

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(B) Let the distance between the two mirrors be $h = 0.2 \ m$ and the length of the mirrors be $L = 2\sqrt{3} \ m$. The angle of incidence is $i = 30^

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$30$

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(B) Let the distance between the two mirrors be $h = 0.2 \ m$ and the length of the mirrors be $L = 2\sqrt{3} \ m$. The angle of incidence is $i = 30^{\circ}$.The horizontal distance $d$ covered by the ray between two consecutive reflections is given by:$d = h 	an(i) = 0.2 	an(30^{\circ}) = 0.2 	imes \frac{1}{\sqrt{3}} = \frac{0.2}{\sqrt{3}} \ m$.The total number of reflections $n$ is given by the ratio of the total length $L$ to the horizontal distance $d$ covered per reflection:$n = \frac{L}{d} = \frac{2\sqrt{3}}{0.2 / \sqrt{3}} = \frac{2 	imes 3}{0.2} = \frac{6}{0.2} = 30$.Thus,the maximum number of reflections the ray will undergo is $30$.

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