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(C) For a concave mirror, the magnification $m$ is given by $m = -v/u$. Given that the image is real and $n$ times the size of the object, the magnifi

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$[(n + 1) / n] f$

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(C) For a concave mirror, the magnification $m$ is given by $m = -v/u$. Given that the image is real and $n$ times the size of the object, the magnification $m = -n$.Thus, $-n = -v/u$, which implies $v = nu$.Using the mirror formula: $1/f = 1/v + 1/u$.Substituting $v = nu$: $1/f = 1/(nu) + 1/u$.$1/f = (1 + n) / (nu)$.Rearranging for $u$: $u = f(n + 1) / n = [(n + 1) / n] f$.Therefore, the distance of the object from the mirror is $[(n + 1) / n] f$.

$A$ concave mirror of focal length $f$ forms an image $n$ times the size of the object. If the image is real, then the distance of the object from the mirror is .......

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