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(A) The magnifying power $(M)$ of an astronomical telescope in normal adjustment is given by $M = f_o / f_e$,where $f_o$ is the focal length of the ob

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decrease

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(A) The magnifying power $(M)$ of an astronomical telescope in normal adjustment is given by $M = f_o / f_e$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.The length of the telescope tube $(L)$ is given by $L = f_o + f_e$.To increase the length of the tube $(L)$,we must increase the focal lengths of the lenses ($f_o$ or $f_e$).Since the magnifying power $M$ is inversely proportional to the focal length of the eyepiece $(f_e)$,increasing $f_e$ to increase the tube length will result in a decrease in the magnifying power $(M)$.Therefore,the magnifying power will decrease.

When the tube length of an astronomical telescope is increased,its magnifying power will .......

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