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(D) Let the voltage of the source be $V$ and the resistance of each bulb be $R$. Since each bulb is designed to consume power $P$ at voltage $V$,we ha

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$P/n$

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(D) Let the voltage of the source be $V$ and the resistance of each bulb be $R$. Since each bulb is designed to consume power $P$ at voltage $V$,we have $P = V^2/R$,which implies $R = V^2/P$. When $n$ such bulbs are connected in series,the total resistance of the circuit becomes $R_{eq} = nR$. The total power consumed by the series combination is $P_{total} = V^2 / R_{eq}$. Substituting $R_{eq} = nR$,we get $P_{total} = V^2 / (nR) = (1/n) * (V^2/R)$. Since $P = V^2/R$,the total power is $P_{total} = P/n$.

$n$ identical bulbs,each designed to consume power $P$ at a certain voltage source,are connected in series across the same source. The total power consumed by them is:

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