If M = mass,L = length,T = time,and I = elect | vedclass

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Question

(A) According to Ohm's law,$R = \frac{V}{I}$.Since potential difference $V = \frac{W}{q}$,where $W$ is work and $q$ is charge,we have $R = \frac{W}{qI

Vedclass · Accepted Answer

$M^1L^2T^{-3}I^{-2}$

Vedclass · Answer

(A) According to Ohm's law,$R = \frac{V}{I}$.Since potential difference $V = \frac{W}{q}$,where $W$ is work and $q$ is charge,we have $R = \frac{W}{qI}$.We know that $q = I 	imes T$.Substituting this into the equation,we get $R = \frac{W}{(I 	imes T) 	imes I} = \frac{W}{I^2 T}$.The dimensional formula for work $W$ is $[M^1L^2T^{-2}]$,for current $I$ is $[I^1]$,and for time $T$ is $[T^1]$.Therefore,the dimensional formula for $R$ is $\frac{[M^1L^2T^{-2}]}{[I^2][T^1]} = [M^1L^2T^{-3}I^{-2}]$.

If $M =$ mass,$L =$ length,$T =$ time,and $I =$ electric current,then the dimensional formula for electrical resistance $R$ is:

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