(A) The circuit represents a Wheatstone bridge configuration. When no current flows through the central $5\,\Omega$ resistor,the bridge is balanced. A

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(A) The circuit represents a Wheatstone bridge configuration. When no current flows through the central $5\,\Omega$ resistor,the bridge is balanced. According to the balanced Wheatstone bridge condition,the ratio of the resistances in the opposite arms must be equal: $\frac{X}{18} = \frac{2}{6}$ $X = \frac{18 \times 2}{6}$ $X = 6\,\Omega$.

Class 12 Physics Current Electricity Kirchhoff's Law and Whitestone Bridge Circuit solving

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In the circuit shown in the figure,when no current flows through the $5\,\Omega$ resistor,the value of the resistor $X$ will be ........... $\Omega$.

A
$6$
B
$9$
C
$4$
D
$10$

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Kirchhoff's Law and Whitestone Bridge Circuit solving

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In the circuit shown in the figure,when no current flows through the $5\,\Omega$ resistor,the value of the resistor $X$ will be ........... $\Omega$.

Similar Questions

For the circuit given below,the Kirchhoff's loop rule for the loop $BCDEB$ is given by the equation:

In the given circuit diagram,a wire is joining points $B$ and $D$. The current in this wire is ............. $A$.

If the Wheatstone bridge shown in the figure is balanced,then the values of $R_1$ and $R_2$ are ...... $\Omega$ and ...... $\Omega$ respectively.

Calculate the equivalent resistance between $A$ and $B$.

The current $I$ in the circuit shown is:

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