Find the number of electrons flowing through | vedclass

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(B) Given: Power $P = 60 \ W$,Voltage $V = 120 \ V$,Time $t = 1 \ s$.Using the formula $P = VI$,the current $I$ is given by:$I = \frac{P}{V} = \frac{6

Vedclass · Accepted Answer

$3.125 	imes 10^{18}$

Vedclass · Answer

(B) Given: Power $P = 60 \ W$,Voltage $V = 120 \ V$,Time $t = 1 \ s$.Using the formula $P = VI$,the current $I$ is given by:$I = \frac{P}{V} = \frac{60}{120} = 0.5 \ A$.We know that the total charge $Q$ flowing in time $t$ is $Q = It$.Also,the quantization of charge is given by $Q = ne$,where $n$ is the number of electrons and $e = 1.6 	imes 10^{-19} \ C$ is the charge of an electron.Equating the two expressions for $Q$:$ne = It$$n = \frac{It}{e} = \frac{0.5 	imes 1}{1.6 	imes 10^{-19}}$$n = \frac{0.5}{1.6} 	imes 10^{19} = 0.3125 	imes 10^{19} = 3.125 	imes 10^{18}$.Therefore,the number of electrons is $3.125 	imes 10^{18}$.

Find the number of electrons flowing through the filament of a $120 \ V, 60 \ W$ electric lamp in one second.

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