When the switch K is closed at t = 0,what can | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) At $t = 0$,the capacitor acts as a short circuit (uncharged). The total resistance in the circuit is $1000\,\Omega$. Thus,the current $I = \frac{V

Vedclass · Accepted Answer

At $t = 0$,$I = 2\,mA$ and as time passes,it becomes $1\,mA$

Vedclass · Answer

(C) At $t = 0$,the capacitor acts as a short circuit (uncharged). The total resistance in the circuit is $1000\,\Omega$. Thus,the current $I = \frac{V}{R} = \frac{2\,V}{1000\,\Omega} = 2\,mA$.As $t 	o \infty$,the capacitor becomes fully charged and acts as an open circuit. The current now flows through the series combination of the two $1000\,\Omega$ resistors. The total resistance is $1000\,\Omega + 1000\,\Omega = 2000\,\Omega$. Thus,the current $I = \frac{V}{R_{total}} = \frac{2\,V}{2000\,\Omega} = 1\,mA$.

When the switch $K$ is closed at $t = 0$,what can be said about the current passing through the resistor $AB$ in the given circuit?

Similar Questions

During charging and discharging of a capacitor:

At time $t=0$,a battery of $10 \ V$ is connected across points $A$ and $B$ in the given circuit. If the capacitors have no charge initially,at what time (in seconds) does the voltage across them become $4 \ V$? [Take $\ln 5=1.6, \ln 3=1.1$]

Switch $S$ of the circuit shown in the figure is in position $1$ for a long time. At instant $t = 0$,it is thrown from position $1$ to $2$. Find the thermal power $P_1(t)$ generated in resistance $R_1$.

The charge on a capacitor of capacitance $10\,\mu F$ connected as shown in the figure is.......$\mu C$

$A$ resistance $R$ and a capacitance $C$ are connected in series to a battery of negligible internal resistance through a key. The key is closed at $t = 0$. If after $t \, s$ the voltage across the capacitance is seven times the voltage across $R$,the value of $t$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module