Some bulbs are connected in series to a 220, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The power consumed by a series circuit is given by $P = \frac{V^2}{R_{eq}}$,where $R_{eq}$ is the equivalent resistance of the circuit.Since the s

Vedclass · Accepted Answer

Increase

Vedclass · Answer

(A) The power consumed by a series circuit is given by $P = \frac{V^2}{R_{eq}}$,where $R_{eq}$ is the equivalent resistance of the circuit.Since the supply voltage $V$ is constant,$P \propto \frac{1}{R_{eq}}$.When one bulb is removed from the series combination,the total equivalent resistance $R_{eq}$ of the circuit decreases.Because $P$ is inversely proportional to $R_{eq}$,a decrease in resistance leads to an increase in the total power consumed by the remaining bulbs.Therefore,the brightness in the room will increase.

Some bulbs are connected in series to a $220\, V$ supply. If one bulb gets fused and the remaining bulbs are reconnected in series to the same supply,the brightness in the room will:

Similar Questions

Three unequal resistors in parallel are equivalent to a resistance of $1 \ \Omega$. If two of them are in the ratio $1:2$ and if no resistance value is fractional,then the largest of the three resistances in ohms is

If three resistors of resistance $2 \,\Omega$,$4 \,\Omega$ and $5 \,\Omega$ are connected in parallel,then the total resistance of the combination will be:

Three conductors draw currents of $1 \,A, 2 \,A$ and $3 \,A$ respectively, when connected in turn across a battery. If they are connected in series and the combination is connected across the same battery, the current drawn will be

The current $I$ in the network shown in the figure is .......... $A$.

You are given $10$ resistors each of resistance $1 \ \Omega$. First,they are connected to obtain the possible minimum resistance. Then,they are connected to obtain the possible maximum resistance. The ratio of minimum and maximum resistance is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module