In a closed circuit,the current at time t is | vedclass

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(B) The current is defined as the rate of flow of charge: $I = \frac{dQ}{dt} = 4 - 0.08t$. To find the total charge $Q$ passing through the cross-sect

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$6.25 	imes 10^{20}$

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(B) The current is defined as the rate of flow of charge: $I = \frac{dQ}{dt} = 4 - 0.08t$. To find the total charge $Q$ passing through the cross-section in $50 \ s$,we integrate the current with respect to time from $t = 0$ to $t = 50 \ s$: $Q = \int_{0}^{50} (4 - 0.08t) dt = [4t - \frac{0.08t^2}{2}]_{0}^{50} = [4(50) - 0.04(50)^2] = 200 - 0.04(2500) = 200 - 100 = 100 \ C$. Using the quantization of charge formula $Q = ne$,where $e = 1.6 	imes 10^{-19} \ C$ is the charge of an electron: $n = \frac{Q}{e} = \frac{100}{1.6 	imes 10^{-19}} = 6.25 	imes 10^{20}$ electrons.

In a closed circuit,the current at time $t$ is given by $I = 4 - 0.08t$. The number of electrons passing through the cross-section of the conductor in $50 \ s$ will be:

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