In the network shown in the figure,the potent | vedclass

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(B) First,calculate the equivalent resistance of the parallel combination of $4R$ and $2R$ resistors:$R_p = \frac{4R 	imes 2R}{4R + 2R} = \frac{8R^2}

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$4E/7$

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(B) First,calculate the equivalent resistance of the parallel combination of $4R$ and $2R$ resistors:$R_p = \frac{4R 	imes 2R}{4R + 2R} = \frac{8R^2}{6R} = \frac{4}{3}R$Now,calculate the total resistance of the circuit by adding the series resistor $R$:$R_{total} = R + R_p = R + \frac{4}{3}R = \frac{7}{3}R$The total current $I$ flowing from the cell is:$I = \frac{E}{R_{total}} = \frac{E}{(7/3)R} = \frac{3E}{7R}$The potential difference across the parallel combination (which is the same for both $4R$ and $2R$ resistors) is:$V = I 	imes R_p = \left(\frac{3E}{7R}ight) 	imes \left(\frac{4}{3}Right) = \frac{4E}{7}$Thus,the potential difference across the $2R$ resistor is $4E/7$.

In the network shown in the figure,the potential difference across the $2R$ resistor is...... (The cell has an $emf$ $E$ and no internal resistance).

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