P and Q are two identical wires of resistance | vedclass

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(D) The total resistance of the wire $PQ$ is $2000\, \Omega$. Since $M$ is the midpoint, the resistance of segment $PM$ is $1000\, \Omega$ and the res

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$50$

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(D) The total resistance of the wire $PQ$ is $2000\, \Omega$. Since $M$ is the midpoint, the resistance of segment $PM$ is $1000\, \Omega$ and the resistance of segment $MQ$ is $1000\, \Omega$.The voltmeter of resistance $R_v = 1000\, \Omega$ is connected in parallel with the segment $PM$ $(R_{PM} = 1000\, \Omega)$.The equivalent resistance of the parallel combination of the voltmeter and segment $PM$ is:$R_p = \frac{R_v 	imes R_{PM}}{R_v + R_{PM}} = \frac{1000 	imes 1000}{1000 + 1000} = 500\, \Omega$.The total resistance of the circuit is $R_{eq} = R_p + R_{MQ} = 500\, \Omega + 1000\, \Omega = 1500\, \Omega$.The total current in the circuit is $I = \frac{V}{R_{eq}} = \frac{150\, V}{1500\, \Omega} = 0.1\, A$.The voltage across the parallel combination (which is the voltmeter reading) is $V_v = I 	imes R_p = 0.1\, A 	imes 500\, \Omega = 50\, V$.

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