R_1 and R_2 are two resistors made of differe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the resistances at $0^{\circ}C$ be $R_{01}$ and $R_{02}$.At temperature $	heta$,the resistances are given by:$R_1 = R_{01}(1 + \alpha 	heta)

Vedclass · Accepted Answer

$\beta/\alpha$

Vedclass · Answer

(D) Let the resistances at $0^{\circ}C$ be $R_{01}$ and $R_{02}$.At temperature $	heta$,the resistances are given by:$R_1 = R_{01}(1 + \alpha 	heta)$$R_2 = R_{02}(1 - \beta 	heta)$The total resistance in series is $R_s = R_1 + R_2$.$R_s = R_{01}(1 + \alpha 	heta) + R_{02}(1 - \beta 	heta)$$R_s = (R_{01} + R_{02}) + 	heta(R_{01}\alpha - R_{02}\beta)$For the total resistance $R_s$ to be independent of temperature $	heta$,the coefficient of $	heta$ must be zero:$R_{01}\alpha - R_{02}\beta = 0$$R_{01}\alpha = R_{02}\beta$Therefore,the ratio of the resistances is $\frac{R_{01}}{R_{02}} = \frac{\beta}{\alpha}$.

Similar Questions

$A$ bulb rated at $(100\,W, 200\,V)$ is used on a $100\,V$ line. The current in the bulb is

The reading of the ammeter in the adjoining figure will be .............. $A$.

If the rheostat slider were to move from the extreme right to the far left,how will the reading of voltmeter $V_1$ change?

When a current of $2 \ A$ flows through a conductor,$80 \ J$ of heat is produced in $10 \ s$. The resistance of the conductor is ........... $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module