The magnitude of the vector |2hat{i} - hat{j} | vedclass

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Question

(A) The magnitude of a vector $\vec{A} = A_x\hat{i} + A_y\hat{j} + A_z\hat{k}$ is given by $|\vec{A}| = \sqrt{A_x^2 + A_y^2 + A_z^2}$.Given vector is

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$\sqrt{30}$

Vedclass · Answer

(A) The magnitude of a vector $\vec{A} = A_x\hat{i} + A_y\hat{j} + A_z\hat{k}$ is given by $|\vec{A}| = \sqrt{A_x^2 + A_y^2 + A_z^2}$.Given vector is $\vec{A} = 2\hat{i} - 1\hat{j} - 5\hat{k}$.Here,$A_x = 2$,$A_y = -1$,and $A_z = -5$.Substituting these values into the formula:$|\vec{A}| = \sqrt{(2)^2 + (-1)^2 + (-5)^2}$$|\vec{A}| = \sqrt{4 + 1 + 25}$$|\vec{A}| = \sqrt{30}$.

Column $-I$	Column $-II$
$(1)$ Angular momentum	$(a)$ Scalar
$(2)$ Potential energy	$(b)$ Vector
	$(c)$ Unit vector

The magnitude of the vector $|2\hat{i} - \hat{j} - 5\hat{k}|$ is .....

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