Two coherent sources have different intensiti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the intensities of the two sources be $I_1$ and $I_2$. The ratio of maximum to minimum intensity in an interference pattern is given by the fo

Vedclass · Accepted Answer

$9:4$

Vedclass · Answer

(C) Let the intensities of the two sources be $I_1$ and $I_2$. The ratio of maximum to minimum intensity in an interference pattern is given by the formula:$\frac{I_{max}}{I_{min}} = \frac{(\sqrt{I_1} + \sqrt{I_2})^2}{(\sqrt{I_1} - \sqrt{I_2})^2} = 25$Taking the square root on both sides:$\frac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sqrt{I_2}} = \sqrt{25} = 5$By applying componendo and dividendo:$\frac{(\sqrt{I_1} + \sqrt{I_2}) + (\sqrt{I_1} - \sqrt{I_2})}{(\sqrt{I_1} + \sqrt{I_2}) - (\sqrt{I_1} - \sqrt{I_2})} = \frac{5 + 1}{5 - 1}$$\frac{2\sqrt{I_1}}{2\sqrt{I_2}} = \frac{6}{4} = \frac{3}{2}$$\frac{\sqrt{I_1}}{\sqrt{I_2}} = \frac{3}{2}$Squaring both sides,we get:$\frac{I_1}{I_2} = \frac{9}{4}$

Two coherent sources have different intensities. They produce an interference pattern. If the ratio of maximum to minimum intensities is $25:1$,find the ratio of the intensities of the sources.

Similar Questions

When two light waves of equal intensity superimpose, the maximum intensity obtained is $I$. If the intensity of one of the waves is quadrupled, then the maximum intensity obtained is

Two monochromatic light beams of intensity $16$ and $9$ units are interfering. The ratio of intensities of bright and dark parts of the resultant pattern is

The wave nature of light is verified by

Two light waves of intensities $I$ and $4I$ superpose at a point with a phase difference of $\pi / 2$. Calculate the resultant amplitude at that point.

Vedclass Test Series

Exam Paper Generator

Online Exam Module