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(D) In Young's double-slit experiment,the condition for constructive interference (bright fringe) is given by the path difference $\Delta x = n\lambda

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$6\pi$

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(D) In Young's double-slit experiment,the condition for constructive interference (bright fringe) is given by the path difference $\Delta x = n\lambda$,where $n = 0, 1, 2, 3, \dots$ represents the order of the fringe.The relationship between path difference $\Delta x$ and phase difference $\delta\phi$ is given by $\delta\phi = \frac{2\pi}{\lambda} \Delta x$.Substituting $\Delta x = n\lambda$ into the phase difference formula,we get $\delta\phi = \frac{2\pi}{\lambda} (n\lambda) = 2n\pi$.For the third bright fringe,$n = 3$.Therefore,the phase difference is $\delta\phi = 2 	imes 3 	imes \pi = 6\pi$ radians.

In a Young's double-slit experiment,the wavelength of light used is $6000 \, \mathring A$. The phase difference between the central bright fringe and the third bright fringe is .......

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