In an interference pattern,the fringe width is $\beta$. If the frequency of the source is doubled,the fringe width becomes .....

In a Young's double-slit experiment,light of two wavelengths $6500 \, \mathring A$ and $5200 \, \mathring A$ is used. Find the distance of the third bright fringe from the central maximum for the wavelength $6500 \, \mathring A$. The distance between the two slits is $2 \, mm$ and the distance between the plane of the slits and the screen is $120 \, cm$.

What happens to the fringe width in Young's double-slit experiment when it is performed in water instead of air?

Two slits are separated by a distance of $0.5\, mm$ and illuminated with light of $\lambda = 6000\ \mathring A$. If the screen is placed $2.5\, m$ from the slits,the distance of the third bright fringe from the centre will be........$mm$.

In a Young's double-slit experiment,the distance between the two slits is $d = \lambda / 4$,where $\lambda$ is the wavelength of the light used. The initial phase difference is $\pi / 4$. What is the intensity at $\theta = 30^o$?

$A$ Young's double-slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is